A Treatise on Conic Sections: Containing an Account of Some of the Most Important Modern Algebraic and Geometric MethodsLongmans, Green, and Company, 1879 - Broj stranica: 399 |
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Rezultati 1 - 5 od 93.
Stranica 3
... hence PQ2 = PS " + SQ , but PS = PM- QM ' = y ' -y " , ☎2 = PQ2 = ( x ' — x ′′ ) 2 + ( y ' — y ′′ ) ” . - - To express the distance of any point from the origin , we must make " = 0 , y ′′ = 0 in the above , and we find 82 = x22 + y22 ...
... hence PQ2 = PS " + SQ , but PS = PM- QM ' = y ' -y " , ☎2 = PQ2 = ( x ' — x ′′ ) 2 + ( y ' — y ′′ ) ” . - - To express the distance of any point from the origin , we must make " = 0 , y ′′ = 0 in the above , and we find 82 = x22 + y22 ...
Stranica 20
... Hence we learn that A √ ( A2 + B2 ) B and are re- √ ( A3 + B * ) с spectively the cosine and sine of the angle which the per- pendicular from the origin on the line ( Ax + By + C = 0 ) makes with the axis of 20 , perpendicular , and ...
... Hence we learn that A √ ( A2 + B2 ) B and are re- √ ( A3 + B * ) с spectively the cosine and sine of the angle which the per- pendicular from the origin on the line ( Ax + By + C = 0 ) makes with the axis of 20 , perpendicular , and ...
Stranica 28
... hence RT = QS = y ' cosß ; x ' cosa + y ' cos3 = OR . S Subtract OP , the perpendicular from the origin , and K M x ' cosa + y ' cosẞ - p = PR = the perpendicular QV . But if in the figure the point Q had been taken on the side of the ...
... hence RT = QS = y ' cosß ; x ' cosa + y ' cos3 = OR . S Subtract OP , the perpendicular from the origin , and K M x ' cosa + y ' cosẞ - p = PR = the perpendicular QV . But if in the figure the point Q had been taken on the side of the ...
Stranica 48
... Hence , if the equation of a right line contain an indeterminate quantity in the first degree , the right line will always pass through a fixed point . Ex . 1. Given vertical angle of a triangle and the sum of the reciprocals of the ...
... Hence , if the equation of a right line contain an indeterminate quantity in the first degree , the right line will always pass through a fixed point . Ex . 1. Given vertical angle of a triangle and the sum of the reciprocals of the ...
Stranica 51
... hence and m2 - 2am + a2 = a2 + c2 2ac sin 0 , α = m2 - c2 2 ( m - c sin 0 ) * Thus we have expressed a in terms of @ and constants , and it only remains to find an expression for tan C. Now but hence b sin C tan C = b ( 1 + cos C ...
... hence and m2 - 2am + a2 = a2 + c2 2ac sin 0 , α = m2 - c2 2 ( m - c sin 0 ) * Thus we have expressed a in terms of @ and constants , and it only remains to find an expression for tan C. Now but hence b sin C tan C = b ( 1 + cos C ...
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Ostala izdanja - Prikaži sve
A Treatise on Conic Sections: Containing an Account of Some of the Most ... George Salmon Pregled nije dostupan - 2015 |
A Treatise on Conic Sections: Containing an Account of Some of the Most ... George Salmon Pregled nije dostupan - 2016 |
Uobičajeni izrazi i fraze
anharmonic ratio asymptotes ax² axes bisected by² centre chord of contact circumscribing coefficients coincide common tangents condition conic having double conic section conic touching conjugate diameters coordinates corresponding denote determine directrix double contact drawn ellipse equal find the equation find the locus fixed line fixed point foci focus four points given conic given line given point harmonic Hence hyperbola imaginary points infinite distance inscribed intercept last Article line at infinity line joining line meets meet the curve middle points mẞ origin parabola parallel Pascal's theorem perpendicular point of contact point x'y points at infinity points of intersection polar pole proved quadratic quadrilateral radical axis radius vector reciprocal rectangle represents right angles right line second degree sides square substituting tangential equation theorem trilinear coordinates values vanish vertex vertices
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